เฉลย การเขียนโปรเเกรมตามเงื่อนไข เเละเเสดงผลตามโจทย์
#include<stdio.h>
int main(){
printf(“Program Calculator\n”);
int num, max, min,choice;
float total;
printf(“Please input number : “);
scanf(“%d”,&num);
total = num;
max = min = num;
do{
printf(“\n\t1. Add 2. Sub 3. Multiply 4. Divide 5. Total\n\n”);
printf(“please select : “);
scanf(“%d”,&choice);
switch(choice){
case 1: printf(“+\n”);
printf(“Please input number : “);
scanf(“%d”,&num);
total = total + num;
printf(“\n%f\n”,total);
break;
case 2: printf(“-\n”);
printf(“Please input number : “);
scanf(“%d”,&num);
total = total – num;
printf(“\n%f\n”,total);
break;
case 3: printf(“x\n”);
printf(“Please input number : “);
scanf(“%d”,&num);
total = total * num;
printf(“\n%f\n”,total);
break;
case 4: printf(“/\n”);
printf(“Please input number : “);
scanf(“%d”,&num);
total = total * 1.0 /num;
printf(“\n%f\n”,total);
break;
case 5: break;
default : printf(“select 1 – 5 only\n”);
}
if(num > max)
max = num;
if(num < min)
min = num;
}while(choice != 5);
printf(“===================\n”);
printf(“total = %f\n”,total);
printf(“Max = %d\n”, max);
printf(“Min = %d\n”, min);
int def, i, j;
def = max – min;
printf(“\n\n\n==========\n”);
for(i = 1; i<=def; i++){
for(j = 1; j<=def; j++){
printf(“*”);
}
printf(“\n”);
}
printf(“===========\n”);
for(i = 1; i<=def; i++){
for(j = 1; j<=i; j++){
printf(“*”);
}
printf(“\n”);
}
printf(“===========\n”);
for(i = 1; i<=def; i++){
for(j = 1; j<=def; j++){
if(i == 1||i == def|| j==1 || j==def){
printf(“*”);
}else{
printf(” “);
}
}
printf(“\n”);
}
printf(“===========\n”);
}
//ขอให้สนุกกับการเขียนโปรเเกรมครับ>-<
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